第7章

类别:其他 作者:Samuel Scolnicov字数:2457更新时间:18/12/17 17:06:17
Andinthisway,theone,ifithasbeing,hasturnedouttobemany? True。 Butnow,letusabstracttheonewhich,aswesay,partakesofbeing,andtrytoimagineitapartfromthatofwhich,aswesay,itpartakes—willthisabstractonebeoneonlyormany? One,Ithink。 Letussee:—Mustnotthebeingofonebeotherthanone?fortheoneisnotbeing,but,consideredasone,onlypartookofbeing? Certainly。 Ifbeingandtheonebetwodifferentthings,itisnotbecausetheoneisonethatitisotherthanbeing;norbecausebeingisbeingthatitisotherthantheone;buttheydifferfromoneanotherinvirtueofothernessanddifference。 Certainly。 Sothattheotherisnotthesameeitherwiththeoneorwithbeing? Certainlynot。 Andthereforewhetherwetakebeingandtheother,orbeingandtheone,ortheoneandtheother,ineverysuchcasewetaketwothings,whichmayberightlycalledboth。 Howso。 Inthisway—youmayspeakofbeing? Yes。 Andalsoofone? Yes。 Thennowwehavespokenofeitherofthem? Yes。 Well,andwhenIspeakofbeingandone,Ispeakofthemboth? Certainly。 AndifIspeakofbeingandtheother,oroftheoneandtheother—inanysuchcasedoInotspeakofboth? Yes。 Andmustnotthatwhichiscorrectlycalledboth,bealsotwo? Undoubtedly。 Andoftwothingshowcaneitherbyanypossibilitynotbeone? Itcannot。 Then,iftheindividualsofthepairaretogethertwo,theymustbeseverallyone? Clearly。 Andifeachofthemisone,thenbytheadditionofanyonetoanypair,thewholebecomesthree? Yes。 Andthreeareodd,andtwoareeven? Ofcourse。 Andiftherearetwotheremustalsobetwice,andiftherearethreetheremustbethrice;thatis,iftwiceonemakestwo,andthriceonethree? Certainly。 Therearetwo,andtwice,andthereforetheremustbetwicetwo;andtherearethree,andthereisthrice,andthereforetheremustbethricethree? Ofcourse。 Iftherearethreeandtwice,thereistwicethree;andiftherearetwoandthrice,thereisthricetwo? Undoubtedly。 Here,then,wehaveeventakeneventimes,andoddtakenoddtimes,andeventakenoddtimes,andoddtakeneventimes。 True。 Andifthisisso,doesanynumberremainwhichhasnonecessitytobe? Nonewhatever。 Thenifoneis,numbermustalsobe? Itmust。 Butifthereisnumber,theremustalsobemany,andinfinitemultiplicityofbeing;fornumberisinfiniteinmultiplicity,andpartakesalsoofbeing:amInotright? Certainly。 Andifallnumberparticipatesinbeing,everypartofnumberwillalsoparticipate? Yes。 Thenbeingisdistributedoverthewholemultitudeofthings,andnothingthatis,howeversmallorhowevergreat,isdevoidofit?And,indeed,theverysuppositionofthisisabsurd,forhowcanthatwhichis,bedevoidofbeing? Innoway。 Anditisdividedintothegreatestandintothesmallest,andintobeingofallsizes,andisbrokenupmorethanallthings;thedivisionsofithavenolimit。 True。 Thenithasthegreatestnumberofparts? Yes,thegreatestnumber。 Isthereanyofthesewhichisapartofbeing,andyetnopart? Impossible。 Butifitisatallandsolongasitis,itmustbeone,andcannotbenone? Certainly。 Thentheoneattachestoeverysinglepartofbeing,anddoesnotfailinanypart,whethergreatorsmall,orwhatevermaybethesizeofit? True。 Butreflect:—anoneinitsentirety,beinmanyplacesatthesametime? No;Iseetheimpossibilityofthat。 Andifnotinitsentirety,thenitisdivided;foritcannotbepresentwithallthepartsofbeing,unlessdivided。 True。 Andthatwhichhaspartswillbeasmanyasthepartsare? Certainly。 Thenwewerewronginsayingjustnow,thatbeingwasdistributedintothegreatestnumberofparts。Foritisnotdistributedintopartsmorethantheone,intopartsequaltotheone;theoneisneverwantingtobeing,orbeingtotheone,butbeingtwotheyareco—equalandcoextensive。 Certainlythatistrue。 Theoneitself,then,havingbeenbrokenupintopartsbybeing,ismanyandinfinite? True。 Thennotonlytheonewhichhasbeingismany,buttheoneitselfdistributedbybeing,mustalsobemany? Certainly。 Further,inasmuchasthepartsarepartsofawhole,theone,asawhole,willbelimited;forarenotthepartscontainedthewhole? Certainly。 Andthatwhichcontains,isalimit? Ofcourse。 Thentheoneifithasbeingisoneandmany,wholeandparts,havinglimitsandyetunlimitedinnumber? Clearly。 Andbecausehavinglimits,alsohavingextremes? Certainly。 Andifawhole,havingbeginningandmiddleandend。Forcananythingbeawholewithoutthesethree?Andifanyoneofthemiswantingtoanything,willthatanylongerbeawhole? No。 Thentheone,asappears,willhavebeginning,middle,andend。 Itwill。 But,again,themiddlewillbeequidistantfromtheextremes;oritwouldnotbeinthemiddle? Yes。 Thentheonewillpartakeoffigure,eitherrectilinearorround,oraunionofthetwo? True。 Andifthisisthecase,itwillbebothinitselfandinanothertoo。 How? Everypartisinthewhole,andnoneisoutsidethewhole。 True。 Andallthepartsarecontainedbythewhole? Yes。 Andtheoneisallitsparts,andneithermorenorlessthanall? No。 Andtheoneisthewhole? Ofcourse。 Butifallthepartsareinthewhole,andtheoneisallofthemandthewhole,andtheyareallcontainedbythewhole,theonewillbecontainedbytheone;andthustheonewillbeinitself。 Thatistrue。 Butthen,again,thewholeisnotintheparts—neitherinalltheparts,norinsomeoneofthem。Forifitisinall,itmustbeinone;foriftherewereanyoneinwhichitwasnot,itcouldnotbeinalltheparts;forthepartinwhichitiswantingisoneofall,andifthewholeisnotinthis,howcanitbeinthemall? Itcannot。